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how to calculate ksp from concentration

25/02/2021
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First, write the equation for the dissolving of lead(II) chloride and the ion. negative fourth molar is the equilibrium concentration Ksp=1.17x10^-5. If youd like proof, see how well instant coffee mixes in a cup of cold water compared to a cup of hot water. Ag_{2}CO_{3}, K_{sp} = 8.5*10^{-12} 4. Ask below and we'll reply! What is the equilibrium constant for the reaction of NH3 with water? In the case of a simple 1:1 solid such as AgCl, this would just be the concentration of Ag + or Cl - in the saturated solution. Below is the solubility product equation which is followed by four $K_s_p$ chemistry problems so you can see how to write out $K_s_p$ expressions. Direct link to Darmon's post I assume you mean the hyd, Posted 4 years ago. When you open the can, the pressure decreases, and, if you leave the soda sitting out long enough, the bubbles will eventually disappear because solubility has decreased and they are no longer dissolved in the liquid (theyve bubbled out of the drink). What is the equation for finding the equilibrium constant for a chemical reaction? The presence of How to calculate solubility of salt in water. solution is common to the chloride in lead(II) chloride. The cookie is set by GDPR cookie consent to record the user consent for the cookies in the category "Functional". Whereas solubility is usually expressed in terms of mass of solute per 100 mL of solvent, Ksp is defined in terms of the molar concentrations of the component ions. values. 18.1: Solubility Product Constant, Ksp is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by LibreTexts. Formulate Solubility Reaction Write the balanced solubility reaction equation for the substance you're interested in. Check out Tutorbase! Comparing Q and Ksp enables us to determine whether a precipitate will form when solutions of two soluble salts are mixed. Calculate the concentration of 6.73 g of Na2CO3 dissolved in 250 mL of H2O. Calculate the solubility of Au(OH)3 in water (Ksp=5.5x10^46). of calcium fluoride that dissolves. First, we need to write out the dissociation equation: $K_s_p$=$ [Ag^{+}]^2$ $[SO_4^2]$. not form when two solutions are combined. How to calculate the equilibrium constant given initial concentration? 1) When AgBr dissolves, it dissociates like this: 3) There is a 1:1 molar ratio between the AgBr that dissolves and Ag+ that is in solution. Write the solubility product expression (Ksp) for the decomposition of Ag2CO3. How do you calculate Ksp from concentration? will dissolve in solution to form aqueous calcium two Next we write out the expression for Ksp , then "plug in" the concentrations to obtain the value for Ksp. The K_{sp} of Ag_2SO_3 is 1.50 times 10^{-14}. So 2.1 times 10 to the The $K_s_p$ values are for when the substances are around 25 degrees Celsius, which is standard. But opting out of some of these cookies may affect your browsing experience. How do you calculate the solubility product constant? To calculate exactly how much dissolves, you use K sp, the solubility product constant, along with an expression derived from the solubility equilibrium reaction for the substance. BiOCl has the smaller $K_s_p$ value, so it will precipitate before CuCl. Ksp for sodium chloride is 36 mol^2/litre^2 . The equation for the Ksp of Ca (OH)2 is the concentration [Ca2+] times the concentration [OH-] taken to the second power, since the OH- has a coefficient of 2 in the balanced equation. Found a content error? This is because we were given a molarity for how much Ba3(PO4)2 dissolved, as opposed to a gram amount. Ask questions; get answers. The equilibrium constant for a dissolution reaction, called the solubility product (Ksp), is a measure of the solubility of a compound. How do you find molar solubility given Ksp and molarity? What is the solubility of AgCl in water if Ksp 1.6 10 10? If they asked for the concentration of the chloride anion during equilibrium would you just multiply the molar solubility by two? These cookies will be stored in your browser only with your consent. The College Entrance Examination BoardTM does not endorse, nor is it affiliated in any way with the owner or any content of this site. Calculating Ksp from Solubility Demonstrates calculations used to relate solubility constants to solute concentration. What is concentration in analytical chemistry? The solubility of lead (iii) chloride is 10.85 g/L. Direct link to Jerry J. Francais II's post How do you know what valu, Posted 7 years ago. I assume you mean the hydroxide anion. Calculate the molar solubility of PbCl2 in pure water at 25c. Direct link to Sophie Butt's post At around 4:53, why do yo, Posted 7 years ago. Its solubility product is 1.08 1010 at 25C, so it is ideally suited for this purpose because of its low solubility when a barium milkshake is consumed by a patient. What concentration of SO_3^{2-} is in equilibrium with Ag_2SO_3(s) and 1.80 times 10^{-3} M Ag^+? will form or not, one must examine two factors. A neutral solution is one that has equal concentrations of OH ions and H3O + ions. That gives us X is equal to 2.1 times 10 to the negative fourth. This can be flipped to calculate pH from hydronium concentration: pH = log[H3O +] An acidic solution is one that has an excess of H3O + ions compared to OH ions. First, we need to write out the two equations. Using this equation, Ksp values can be calculated if the concentrations of the ions are known. Calculating General Chemistry: Principles and Modern Applications. with 75.0 mL of 0.000125 M lead(II) nitrate. Legal. When a transparent crystal of calcite is placed over a page, we see two images of the letters. For calcium oxalate monohydrate, the balanced dissolution equilibrium and the solubility product expression (abbreviating oxalate as ox2) are as follows: \(\mathrm{Ca(O_2CCO_2)}\cdot\mathrm{H_2O(s)}\rightleftharpoons \mathrm{Ca^{2+}(aq)}+\mathrm{^-O_2CCO_2^-(aq)}+\mathrm{H_2O(l)}\hspace{5mm}K_{\textrm{sp}}=[\mathrm{Ca^{2+}}][\mathrm{ox^{2-}}]\). We will And molar solubility refers to the concentration of BaCO3 slightly dissolves in water according to the following equation: BaCO3(s) arrow Ba2+(aq) + CO32-(aq). value for calcium fluoride. Putting the values into the Ksp expression, we obtain: Example #4: Calculate the Ksp for Ce(IO3)4, given that its molar solubility is 1.80 x 104 mol/L. What is the Keq What is the equilibrium constant for water? solution at equilibrium. Brackets stand for molar concentration. symbol Ksp. (b) Find the concentration (in M) of iodate ions in a saturat. We now insert the expressions for the equilibrium concentrations of the ions into the solubility product expression (Equation 17.2): This is the molar solubility of calcium phosphate at 25C. Please note, I DID NOT double the F concentration. Direct link to Seth Sturgill's post You actually would use th, Posted 7 years ago. Direct link to Ernest Zinck's post If you have a slightly so, Posted 8 years ago. calcium two plus ions. Pressure can also affect solubility, but only for gases that are in liquids. Henry's law states that the solubility of a gas is directly proportional to the partial pressure of the gas. Upper Saddle River, NJ: Prentice Hall 2007. Mass percent composition (also called mass percent or percent composition) is the easiest way to express the concentration of a solution because no unit conversions are required. In the case of AgBr, the value is 5.71 x 107 moles per liter. If the solubility product of Mg(OH)2 is 2.00 x 10-11 at 25 degrees Celsius, calculate its solubility at that temperature. Substitute these values into the solubility product expression to calculate Ksp. Drown your sorrows in our complete guide to the 11 solubility rules. Substitute these values into the solubility product expression to calculate Ksp. See how other students and parents are navigating high school, college, and the college admissions process. - [Instructor] Changing the pH of a solution can affect the solubility of a slightly soluble salt. Educ. Calculate Ksp using one ion concentration BCchemistry 375 subscribers Subscribe 104 Share 19K views 9 years ago This video shows you how to calculate Ksp when only one ion concentration in. $K_s_p$ is known as the solubility constant or solubility product. Part Five - 256s 5. There is a 1:1 ratio between Hg2Br2 and Hg22+, BUT there is a 1:2 ratio between Hg2Br2 and Br. We've compiled several great study guides for AP Chem, IB Chemistry, and the NY state Chemistry Regents exam. Step 2: Determine the Ksp equation from the dissociation equation. ion as the initial concentration. Petrucci, Ralph H., et al. $K_s_p$ also is an important part of the common ion effect. Convert the solubility of the salt to moles per liter. of fluoride anions, and since there is a coefficient of two in the balanced equation, it's the concentration of 3 years ago GGHS Chemistry. The first, titled Arturo Xuncax, is set in an Indian village in Guatemala. What is the solubility (in g/L) of BaF2 at 25 C? Simply use a scale to measure the mass of the solute and the final solution and express the ratio as a percentage. Direct link to Shariq Khan's post What would you do if you , Posted 7 years ago. If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. equation or the method of successive approximations to solve for x, but (For Mn(OH)2, Ksp = 1.95 x 10^ -6) A) 9.20 B) 2.10 C) 7.00 D) 5.10 E) 11.89, What is the solubility of Fe(OH)2 in 828 mL of NaOH with a pH of 8.08? Why does the solubility constant matter? Consider the general dissolution reaction below (in aqueous solutions): And since it's a one-to-two mole ratio for calcium two plus temperature of 25 degrees, the concentration of a A The only slightly soluble salt that can be formed when these two solutions are mixed is BaSO4 because NaCl is highly soluble. Thus, the Ksp K s p value for CaCl2 C a C l 2 is 21. Given that the concentration of K+ in the final solution is 0.100 %(w/v). Direct link to Nada Youssef's post At 4:55 while he was solv, Posted 6 years ago. The Ksp is 3.4 \times 10^{-11}. IT IS NOT!!! ACT Writing: 15 Tips to Raise Your Essay Score, How to Get Into Harvard and the Ivy League, Is the ACT easier than the SAT? around the world. What does it mean when Ksp is less than 1? And looking at our ICE table, X represents the equilibrium concentration Get the latest articles and test prep tips! Direct link to Brett Kramer's post If they asked for the con, Posted 6 years ago. Understand the definition of Ksp, the Ksp formula, how to calculate Ksp, and how to find molar solubility from Ksp. Oops, looks like cookies are disabled on your browser. However, the molarity of the ions is 2x and 3x, which means that [PO43] = 2.28 107 and [Ca2+] = 3.42 107. Performance cookies are used to understand and analyze the key performance indexes of the website which helps in delivering a better user experience for the visitors. Image used with permisison from Wikipedia. \[Ag_2CrO_{4(s)} \rightleftharpoons 2Ag^+_{(aq)} + CrO^{2-}_{4(aq)}\nonumber \], \[K_{sp} = [Ag^{+}]^2[CrO_4^{2-}]\nonumber \]. Calculate the value of Ksp for Pbl_2. From the balanced dissolution equilibrium, determine the equilibrium concentrations of the dissolved solute ions. We can calculate the molar solubility using Ksp, but we have to know the ions produced by the dissociation during the dissolution of the substance in the solution. Perform the following calculations involving concentrations of iodate ions. And to balance that out, Our vetted tutor database includes a range of experienced educators who can help you polish an essay for English or explain how derivatives work for Calculus. in pure water if the solubility product constant for silver chromate is So Ksp is equal to the concentration of Insert the appropriate values into the solubility product expression and calculate the molar solubility at 25C. fluoride anions raised to the second power. a. adding Na_{2}S ( K_{sp} of NiS = 3 \cdot 10^{-20} ) b. adding Ca(NO_{3})_{2} ( K_{sp} of CaCO_{3} = 4.5 \cdot 10^{-9} ) c. adding K_{2}CO_{3} d. (a) Write the solubility product expression for CuCO_3 (copper(II) carbonate). Because each 1 mol of dissolved calcium oxalate monohydrate dissociates to produce 1 mol of calcium ions and 1 mol of oxalate ions, we can obtain the equilibrium concentrations that must be inserted into the solubility product expression. It represents the level at which a solute dissolves in solution. Inconsolable that you finished learning about the solubility constant? Example: Calculate the solubility product constant for The solubility of an ionic compound decreases in the presence of a common Write the solubility product expression (Ksp) for the decomposition of Ag2CO3. BiAsO_{4}, K_{sp} = 4.4 * 10^{-10} 3. When Hg2Br2 dissolves, it dissociates like this: Important note: it is NOT 2Hg+. What is the [Co2*] in the solution if the Molar Concentration of Cost(aq) absorbance of a sample of the solution is 0.40 M? The larger the real value of the Ksp the more soluble the compound is in solution 2.5 x 103 > 2.5 x 106. How do you find equilibrium constant for a reversable reaction? Calculating the solubility of an ionic compound Solution: 1) Determine moles of HCl . Heres an example: The $K_s_p$ value of $Ag_2SO_4$ ,silver sulfate, is 1.4$10^{}^5$. By clicking Accept, you consent to the use of ALL the cookies. { An_Introduction_to_Solubility_Products : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Calculations_Involving_Solubility_Products : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Common_Ion_Effect : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Pressure_Effects_On_the_Solubility_of_Gases : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Relating_Solubility_to_Solubility_Product : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Solubility : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Solubility_and_Factors_Affecting_Solubility : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "Solubility_Product_Constant,_Ksp" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Solubility_Rules : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Temperature_Effects_on_Solubility : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Temperature_Effects_on_the_Solubility_of_Gases : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "Acid-Base_Equilibria" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Chemical_Equilibria : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Dynamic_Equilibria : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Heterogeneous_Equilibria : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Le_Chateliers_Principle : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Physical_Equilibria : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", Solubilty : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, [ "article:topic", "showtoc:no", "license:ccby", "solubility product constant", "licenseversion:40", "author@Kathryn Rashe", "author@Lisa Peterson" ], https://chem.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fchem.libretexts.org%2FBookshelves%2FPhysical_and_Theoretical_Chemistry_Textbook_Maps%2FSupplemental_Modules_(Physical_and_Theoretical_Chemistry)%2FEquilibria%2FSolubilty%2FSolubility_Product_Constant%252C_Ksp, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), Solubility and Factors Affecting Solubility, status page at https://status.libretexts.org. Calculate the value for K sp of Ca(OH) 2 from this data. For our problem, we're gonna calculate QSP, which has the same form as KSP, the differences the concentrations can be at any moment in time. The solubility product constant for barium sulfate If 2.0 mL of a 0.10 M solution of NaF is added to 128 mL of a 2.0 105M solution of Ca(NO3)2, will CaF2 precipitate? How do you calculate Ksp from solubility? Learn how to balance chemical equations here, or read through these six examples of physical and chemical change. A crystal of calcite (CaCO3), illustrating the phenomenon of double refraction. Second, convert the amount of dissolved lead(II) chloride into moles per How to calculate concentration in mol dm-3. writing -X on the ICE table, where X is the concentration equilibrium concentration. Our new student and parent forum, at ExpertHub.PrepScholar.com, allow you to interact with your peers and the PrepScholar staff. Calculate the equilibrium concentrations when solid Mg(OH)2 is placed in a beaker containing 0.050 M NaOH solution. may not form. 2-] will go up by 1.31 x 10-4 moles/L: x 1/1 -1.31 x 10-4 moles/L > + 1.31 x 10-4 M. The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution. What is the concentration of OH- ions in 0.125M Ba(OH)2 solution? this case does refer to the molar solubility. We also use third-party cookies that help us analyze and understand how you use this website. You actually would use the coefficients when solving for equilibrium expressions. Set up your equation so the concentration C = mass of the solute/total mass of the solution. B) Will mixture precipitate if equal volumes of 3.0 times 10^(-3) M Ba^2+ and 2.0 times 10^(-3) M CO3^2- mixed? This means that, when 2.14 x 104 mole per liter of CaF2 dissolves, it produces 2.14 x 104 mole per liter of Ca2+ and it produces 4.28 x 104 mole per liter of F in solution. How do you calculate the molar concentration of an enzyme? For compounds that dissolve to produce the same number of ions, we can directly compare their K values to determine their relative solubilities. What is the equilibrium constant for the weak acid KHP? Need more help with this topic? All other trademarks and copyrights are the property of their respective owners. The winners are: Princetons Nima Arkani-Hamed, Juan Maldacena, Nathan Seiberg and Edward Witten. textbooks not to put in -X on the ICE table. Given that Ksp = 1.7 x 10-5 for PbCl2, calculate: a) the solubility of PbCl2 in water (in mole/litre) b) the solubility of PbCl2 (in mole/litre) in a 0.15 M solution of MgCl2 in water. Write the balanced equilibrium equation for the dissolution reaction and construct a table showing the concentrations of the species produced in solution. 100 mL of 0.50 M K2SO4 is mixed with 75.0 mL of 0.25 M Al(NO3)3. 1) Here's the chemical equation for the dissolving of MgF2: 3) Based on the stoichiometry of the chemical equation, the [F] is this: To three sig figs, the Ksp is 5.12 x 10-11, Example #10: The molar solubility of Ba3(PO4)2 is 8.89 x 109 M in pure water. A generic salt, AB, has a molar mass of 291 g/mol and a solubility of 5.90 g/L at 25 degrees C. AB (s) A+(aq) + B- (aq) What is the Ksp of this salt at 25 degrees C? solid doesn't change. Direct link to Zenu Destroyer of Worlds (AK)'s post Ice table stands for: A 789 mL NaCl solution is diluted to a volume of 1.26 L and a concentration of 8.00 M. What was the initial concentration? What is the solubility product constant expression for \(MgF_2\)? , Does Wittenberg have a strong Pre-Health professions program? All Modalities Calculating Ksp from Solubility Loading. The Equilibrium constant expression for this reaction can be written as: Ksp = [BaBa +2 ] [SO 4-2] Recall pure solids (and pure liquids) are not included in an equilibrium constant expression. 3.4 \cdot 10^{-9} c. 1.4 \cdot 10^{-8} d.1.5 \cdot 10^{-3}. 0.028 L 0.32 g. What is the difference between Solubility and a Saturated Solution? The first step is to write the dissolution In this section, we discuss the main factors that affect the value of the solubility constant. Direct link to An_Awesome_Person's post At 5:46, is there some re, Posted 5 years ago. Calculate the molar solubility of calcium hydroxide (Ks,-6.0% 106) in pure water and in a solution with a pH of 13.3. Although the amount of solid Ca3(PO4)2 changes as some of it dissolves, its molar concentration does not change. It is given by the formula #-> K_sp = [A^+]^m [B^+]^n#, #color(white)(xxxx) [A^+] and [B^+] = "Concentration of the products"#, #color(white)(xxxx) n and m = "stoichiometric coefficients"#, 10560 views Part Two - 4s 3. What is the rate of production of reactants compared with the rate of production of products at See all questions in Equilibrium Constants. 1 Answer. 1.1 x 10-12. The Beer-Lambert law relates the absorption of light by a solution to the properties of the solution according to the following equation: A = bc, where is the molar absorptivity of the absorbing species, b is the path length, and c is the concentration of the absorbing species. Accessibility StatementFor more information contact us atinfo@libretexts.orgor check out our status page at https://status.libretexts.org. tables (Ksp tables will also do). )%2F18%253A_Solubility_and_Complex-Ion_Equilibria%2F18.1%253A_Solubility_Product_Constant_Ksp, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), \(\dfrac{7.36\times10^{-4}\textrm{ g}}{146.1\textrm{ g/mol}}=5.04\times10^{-6}\textrm{ mol }\mathrm{Ca(O_2CCO_2)\cdot H_2O}\), \(\left(\dfrac{5.04\times10^{-6}\textrm{ mol }\mathrm{Ca(O_2CCO_2\cdot)H_2O}}{\textrm{100 mL}}\right)\left(\dfrac{\textrm{1000 mL}}{\textrm{1.00 L}}\right)=5.04\times10^{-5}\textrm{ mol/L}=5.04\times10^{-5}\textrm{ M}\), \(\begin{align}K_{\textrm{sp}}=[\mathrm{Ca^{2+}}]^3[\mathrm{PO_4^{3-}}]^2&=(3x)^3(2x)^2, \(\left(\dfrac{1.14\times10^{-7}\textrm{ mol}}{\textrm{1 L}}\right)\textrm{100 mL}\left(\dfrac{\textrm{1 L}}{\textrm{1000 mL}} \right )\left(\dfrac{310.18 \textrm{ g }\mathrm{Ca_3(PO_4)_2}}{\textrm{1 mol}}\right)=3.54\times10^{-6}\textrm{ g }\mathrm{Ca_3(PO_4)_2}\), \(\textrm{moles Ba}^{2+}=\textrm{100 mL}\left(\dfrac{\textrm{1 L}}{\textrm{1000 mL}}\right)\left(\dfrac{3.2\times10^{-4}\textrm{ mol}}{\textrm{1 L}} \right )=3.2\times10^{-5}\textrm{ mol Ba}^{2+}\), \([\mathrm{Ba^{2+}}]=\left(\dfrac{3.2\times10^{-5}\textrm{ mol Ba}^{2+}}{\textrm{110 mL}}\right)\left(\dfrac{\textrm{1000 mL}}{\textrm{1 L}}\right)=2.9\times10^{-4}\textrm{ M Ba}^{2+}\), \(\textrm{moles SO}_4^{2-}=\textrm{10.0 mL}\left(\dfrac{\textrm{1 L}}{\textrm{1000 mL}}\right)\left(\dfrac{\textrm{0.0020 mol}}{\textrm{1 L}}\right)=2.0\times10^{-5}\textrm{ mol SO}_4^{2-}\), \([\mathrm{SO_4^{2-}}]=\left(\dfrac{2.0\times10^{-5}\textrm{ mol SO}_4^{2-}}{\textrm{110 mL}} \right )\left(\dfrac{\textrm{1000 mL}}{\textrm{1 L}}\right)=1.8\times10^{-4}\textrm{ M SO}_4^{2-}\).

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